How do you multiply (2x−3y)2?
1 Answer
The answer is
Explanation:
First, we begin by setting it in the form of
(2x−3y)(2x−3y)
Using FOIL, we multiply the first term with the outer and inner term of
4x2−6xy
Now we do the same for the last term of the first part so
−6xy+9y2
So we now have the following terms of
4x2−6xy−6xy+9y2
What we do now is simplify (combine like terms). The final answer is
4x2−12xy+9y2
