How do you multiply #(2x-3y)^2#?

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Answer 1 · 2017-06-06T21:29:24

The answer is #4x^2-12xy+9y^2#.

First, we begin by setting it in the form of

#(2x-3y)(2x-3y)#

Using FOIL, we multiply the first term with the outer and inner term of #(2x)(2x-3y)#. If done right, you should arrive to the answer of

#4x^2-6xy#

Now we do the same for the last term of the first part so #(-3y)(2x-3y) #. The answer should be

#-6xy+9y^2#

So we now have the following terms of

#4x^2-6xy-6xy+9y^2#

What we do now is simplify (combine like terms). The final answer is

#4x^2-12xy+9y^2#