How do you multiply #(2x-3y)^2#?
1 Answer
The answer is
Explanation:
First, we begin by setting it in the form of
#(2x-3y)(2x-3y)#
Using FOIL, we multiply the first term with the outer and inner term of
#4x^2-6xy#
Now we do the same for the last term of the first part so
#-6xy+9y^2#
So we now have the following terms of
#4x^2-6xy-6xy+9y^2#
What we do now is simplify (combine like terms). The final answer is
#4x^2-12xy+9y^2#