# How do you multiply (2yz)(-3y^3)?

May 11, 2018

$- 6 {y}^{4} z$

#### Explanation:

$\left(2 y z\right) \left(- 3 {y}^{3}\right)$ is simply saying: $2 y z \times - 3 {y}^{3}$

If you multiply two exponents together, they powers simply add together.

${a}^{3}$ x ${a}^{2}$ = ${a}^{5}$

$a$ x $b$ = $a b$

Using these rules of algebra you can simplify:

$2 y z \times - 3 {y}^{3}$

to

$- 6 {y}^{4} z$

or simplified version to see clearer:
$\left(- 3 x 2\right) \left(y \times {y}^{3}\right) \left(z \times 1\right)$
$- 6 \times {y}^{4} \times z$
$- 6 {y}^{4} z$