How do you multiply $(3+ 4c ) ( 8- 5c )$ ?

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Answer 1 · 2017-06-29T12:48:05

See a solution process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

$(color(red)(3) + color(red)(4c))(color(blue)(8) - color(blue)(5c))$ becomes:

$(color(red)(3) xx color(blue)(8)) - (color(red)(3) xx color(blue)(5c)) + (color(red)(4c) xx color(blue)(8)) - (color(red)(4c) xx color(blue)(5c))$

$24 - 15c + 32c - 20c^2$

We can now combine like terms:

$24 + (-15 + 32)c - 20c^2$

$24 + 17c - 20c^2$

Or, in standard polynomial form:

$-20c^2 + 17c + 24$

How do you multiply (3+ 4c ) ( 8- 5c )(3+ 4c ) ( 8- 5c )?