How do you multiply #(-3t^2+4t-7)(-2t)#?

1 Answer
Jun 25, 2015

Answer:

#(-3t^2+4t-7)(-2t)#
#color(white)("XXXX")##color(white)("XXXX")##=6t^3-8t^2+14t#

Explanation:

The Distributive Property (of Multiplication over Addition) tells us:
#color(white)("XXXX")##(a+b+c) xx (d) = ad +bd+cd#

So #(-3t^2+4t-7)(-2t)#
#color(white)("XXXX")##= (-3t^2)*(-2t)+(4t)*(-2t)-(7)*(-2t)#

#color(white)("XXXX")##=6t^3-8t^2+14t#