# How do you multiply (3x^2-1)/(4x(x-5)) div ((3x^2)(x-1))/(x-5)?

##### 1 Answer
May 23, 2015

First, remember that when you're dividing two fractions, you invert the other and multiply them instead, like this:

$\frac{3 {x}^{2} - 1}{4 x \left(x - 5\right)} \cdot \frac{x - 5}{\left(3 {x}^{2}\right) \left(x - 1\right)}$

We can already cancel some things that are both dividing and multiplying the equation and, thus, having a null effect in it.

$\frac{3 {x}^{2} - 1}{4 x \cancel{x - 5}} \cdot \frac{\cancel{x - 5}}{\left(3 {x}^{2}\right) \left(x - 1\right)}$

$\frac{3 {x}^{2} - 1}{12 {x}^{4} - 12 {x}^{3}}$