How do you multiply (3x ^ { 2/ 5} - 3y ^ { 1/ 2} ) ( 6x ^ { 2/ 5} - 4y ^ { 1/ 2} )?

1 Answer
Nov 7, 2017

18x^(4/5)*-30x^(2/5)4y^(1/2)*12y

Explanation:

You can use th FOIL method.

(3x^(2/5)-3y^(1/2))(6x^(2/5)-4y^(1/2))

F: 3x^(2/5) * 6x^(2/5)=18x^(4/5)

O: 3x^(2/5)*-4y^(1/2)=-12x^(2/5)4y^(1/2)

I: -3y^(1/2)*6x^(2/5)=-18x^(2/5)y^(1/2)

L: -3y^(1/2)*-4y^(1/2)=12y

Combining like terms, the final answer will be:

18x^(4/5)*-30x^(2/5)4y^(1/2)*12y