How do you multiply #3x^2y^2z(7x^2+2y+z+4w)#?

1 Answer
Apr 27, 2017

Answer:

#21x^4y^2z+6x^2y^3z+3x^2y^2z^2+12x^2y^2zw#

Explanation:

Multiply each part of #7x^2+2y+z+4w# by #3x^2y^2z#
#3x^2y^2z(7x^2)=21x^4y^2z#
#3x^2y^2z(2y)=6x^2y^3z#
#3x^2y^2z(z)=3x^2y^2z^2#
#3x^2y^2z(4w)=12x^2y^2zw#

Then you add each part to get
#21x^4y^2z+6x^2y^3z+3x^2y^2z^2+12x^2y^2zw#