How do you multiply #-3y^2-4y+6+2(y^2+7y-1)#?

Question

1396 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-07-28T09:47:32

You expand the paranthesis and add or subtract like terms.

Your starting expression is

#-3y^2 - 4y + 6 + 2(y^2 + 7y - 1)#

Notice that your expression contains the product between #2# and a paranthesis that features three terms, #y^2#, #7y#, and #-1#.

To expand this paranthesis, multiply each of these terms by #2# to get

#2(y^2 + 7y - 1) = 2* y^2 + 2 * 7y + 2 * (-1)=2y^2 + 14y - 2#

Your expression becomes

#-3y^2 - 4y + 6 + 2y^2 + 14y - 2#

You can simplify this further by grouping like terms together to get

#(-3y^2 + 2y^2) +(14y - 4y) + (6-2)#

#color(green)(-y^2 + 10y + 4)#