# How do you multiply 4m \cdot 7m ^ { 3}?

May 14, 2018

$4 m \setminus \cdot 7 {m}^{3} = \left(4 \cdot 7\right) \cdot {\left(m\right)}^{1 + 3} = 28 \cdot {m}^{4}$

#### Explanation:

show below:

$4 m \setminus \cdot 7 {m}^{3} = \left(4 \cdot 7\right) \cdot {\left(m\right)}^{1 + 3} = 28 \cdot {m}^{4}$

not that

${x}^{n} \cdot {x}^{m} = {x}^{n + m}$

May 14, 2018

$28 {m}^{4}$

#### Explanation:

Multiple $4$ and $7$. you get $28$ then add $m$ and ${m}^{3}$ you get ${m}^{4}$.

May 14, 2018

$28 {m}^{4}$

#### Explanation:

An easy way of doing this would be expanding what each chunk means.
$4 m = 4 \cdot m$
and
$7 {m}^{3} = 7 \cdot m \cdot m \cdot m$
So if you multiply $4 m \cdot 7 {m}^{3}$ you get
$4 \cdot m \cdot 7 \cdot m \cdot m \cdot m$
You can then simplify this.
$4 \cdot 7 = 28$
$m \cdot m \cdot m \cdot m = {m}^{4}$
so $28 \cdot {m}^{4} = 28 {m}^{4}$