# How do you multiply 4x^2(3x^2 + 2x – 1)?

Dec 12, 2015

$12 {x}^{4} + 8 {x}^{3} - 4 {x}^{2}$
Multiply the term, $4 {x}^{2}$, by every term in the trinomial, $3 {x}^{2} + 2 x - 1$:
$4 {x}^{2} \left(3 {x}^{2} + 2 x - 1\right)$
$= 4 {x}^{2} \left(3 {x}^{2}\right) + 4 {x}^{2} \left(2 x\right) - 4 {x}^{2} \left(1\right)$
$= 12 {x}^{4} + 8 {x}^{3} - 4 {x}^{2}$