# How do you multiply ((5x)/(3x +1)) - (1/(9x + 3)) = (7/6)?

May 9, 2015

$\left(9 x + 3\right)$ can be written as $3 \left(3 x + 1\right)$ and 6 can be written as $3 \times 2$

The L.C.M of $\left(3 x + 1\right) , 3 \left(3 x + 1\right)$ and $3 \times 2$ $= 6 \left(3 x + 1\right)$

 (5x xx 6)/(6xx(3x+1) - (1 xx2)/ (6xx(3x+1) $= \frac{7 \times \left(3 x + 1\right)}{6 \times \left(3 x + 1\right)}$

 (30x - 2) / (6xx(3x+1) = (21x +7)/ (6xx(3x+1)

 (30x - 2) / cancel(6xx(3x+1) = (21x +7)/ cancel(6xx(3x+1)

$9 x = 7 + 2$

$x = \frac{9}{9}$

$x = 1$