How do you multiply #((5x)/(3x +1)) - (1/(9x + 3)) = (7/6)#?

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Answer 1 · 2015-05-09T11:45:04

#(9x +3)# can be written as #3(3x +1)# and 6 can be written as # 3 xx 2#

The L.C.M of #(3x +1), 3(3x + 1)# and #3 xx 2# #= 6(3x+1)#

# (5x xx 6)/(6xx(3x+1)## - (1 xx2)/ (6xx(3x+1)# # = (7 xx(3x+1))/(6 xx (3x +1))#

# (30x - 2) / (6xx(3x+1)# #= (21x +7)/ (6xx(3x+1) #

# (30x - 2) / cancel(6xx(3x+1)# #= (21x +7)/ cancel(6xx(3x+1) #

# 9x = 7+2 #

# x = 9/9#

# x =1#