How do you multiply $(- 6 x - 2) (x^{3} - x + 7)$ $(- 6x - 2) ( x ^ { 3} - x + 7)$ ?

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Answer 1 · 2018-06-16T13:12:33

$- 6 x^{4} - 2 x^{3} + 6 x^{2} - 40 x - 14$ $-6x^4-2x^3+6x^2-40x-14$

Expanding we get

$- 6 x^{4} - 2 x^{3} + 6 x^{2} + 2 x - 42 x - 14$ $-6x^4-2x^3+6x^2+2x-42x-14$
combining like Terms we get

$- 6 x^{4} - 2 x^{3} + 6 x^{2} - 40 x - 14$ $-6x^4-2x^3+6x^2-40x-14$

How do you multiply (- 6x - 2) ( x ^ { 3} - x + 7)(−6x−2)(x3−x+7)(- 6x - 2) ( x ^ { 3} - x + 7)?