# How do you multiply (a^2+2)(3a^2-4)?

Here is your problem: (a^2+2)(3a^2−4)
You can think of this problem just like you think of the Distributive Property: ${a}^{2} \left(3 {a}^{2} - 4\right) + 2 \left(3 {a}^{2} - 4\right)$, and then multiply. You should get: $3 {a}^{4} - 4 {a}^{2} + 6 {a}^{2} - 8$, and then gather like terms. You will have: $3 {a}^{4} + 6 {a}^{2} - 8$!
Common mistakes on this problem are usually made when distributing with higher powers like ${a}^{2}$. Be sure to remember that when you multiply with like bases, you add the exponents:
${a}^{2} \cdot 3 {a}^{2} = 3 {a}^{4}$ can be a troublesome first step in the problem.