How do you multiply #(b + 14) ^ { 2}# ?

2 Answers
salamat
Jun 7, 2017

# b^2 + 28 b + 196#

Explanation:

#(b + 14)^2 = (b + 14)(b + 14)#

#= (b * b) + (b * 14) + (14 * b) + (14 * 14)#

# = b^2 + 14 b + 14 b + 196#

#= b^2 + 28 b + 196#

Jim G.
Jun 7, 2017

#b^2+28b+196#

Explanation:

#"express " (b+14)^2=(b+14)(b+14)#

#"each term in the second bracket is multiplied by each "#
#"term in the first bracket as shown below"#

#(color(red)(b+14))(b+14)#

#=color(red)(b)(b+14)color(red)(+14)(b+14)#

#=(color(red)(b)xxb)+(color(red)(b)xx14))+(color(red)(14)xxb)+(color(red)(14)xx14)#

#=b^2+14b+14b+196#

#=b^2+28b+196#

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