Question

How do you multiply `(b^2-6n+9)/(b^2-b-6)div(b^2-9)/4`?

Answer 1

`:.(b^2-6n+9)/(b^2-b-6) xx 4/(b^2-9)`

Explanation:

`(b^2-6n+9)/(b^2-b-6)-:(b^2-9)/4`

to multiply fractions change the`-:`by `xx`sign and
exchange the nominator with the denominator.

`:.(b^2-6n+9)/(b^2-b-6) xx 4/(b^2-9)`