How do you multiply $(k-7)^2$ ?

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Answer 1 · 2015-12-15T02:12:34

$k^2 - 14k + 49$

To square a binomial, use this formula:

$(a+b)^2 = a^2 + 2ab + b^2$

In this case:

$(k-7)^2 = (k)^2 + 2(k)(-7) + (-7)^2 = k^2 - 14k + 49$

How do you multiply (k-7)^2(k-7)^2?