How do you multiply x^ { 2} \cdot x ^ { 8} \cdot x ?

May 25, 2018

Add the exponents ${x}^{2 + 8 + 1}$ = ${x}^{11}$

Explanation:

${x}^{2} = x \times x$
${x}^{8} = x \times x \times x \times x \times x \times x \times x \times x$
$x = {x}^{1} = 1 \times x$

Add all the x's ( 2 + 8 + 1)

By adding all the exponents to multiply

${x}^{2 + 8 + 1} = {x}^{11}$

May 25, 2018

The answer is ${x}^{11}$.

Explanation:

When one has the same number but with several different exponents, the multiplication of the values is the addition of the exponents. In this case, it would be

$2 + 8 + 1$

which would equal $11$.