# How do you multiply (x-3)/(x-5)=3/(x-5)?

We first determine that $x \ne 5$, as this would make the denominators $= 0$, which is not allowed.
Then we can cancel out the $\left(x - 5\right)$ on both sides (=multiply both sides by $x - 5$):
$\to \left(x - 3\right) = 3 \to x = 6$
Answer : $x = 6$