# How do you normalize <2,0,-1>?

##### 1 Answer

Sep 9, 2017

#### Answer:

#### Explanation:

To **normalize** a vector is to find **unit vector** (vector with magnitude/length of one) in the **same direction** as the given vector. This can be accomplished by dividing the given vector by its magnitude.

#hatu=vecv/(|vecv|)#

Given

#abs(vecv)=sqrt((v_x)^2+(v_y)^2+(v_z)^2)#

#=>=sqrt((2)^2+(0)^2+(-1)^2)#

#=>=sqrt(4+0+1)#

#=>=sqrt(5)#

We now have:

#hatu=(<2,0,-1>)/sqrt(5)#

We can also rationalize the denominator on the

#=>hatu=<(2sqrt(5))/5,0,(-sqrt(5))/5>#

Hope that helps!