# How do you normalize #(- 2i - j - k)#?

##### 1 Answer

Aug 14, 2017

#### Explanation:

**Normalization** of a vector is the process of finding a **unit vector** in the same direction of the vector in question.

The equation for the **normalization** of a vector (which I'll call

#(vecv)/(||vecv||)#

where **magnitude** of vector

The **magnitude** of

#||vecv|| = sqrt((-2)^2 + (-1)^2 + (-1)^2) = color(red)(ul(sqrt6#

Thus, the **unit vector** (

#hatv = (-2)/(color(red)(sqrt6))hati - 1/(color(red)(sqrt6))hatj - 1/(color(red)(sqrt6))hatk#

#color(blue)(ulbar(|stackrel(" ")(" "hatv = -sqrt(2/3)hati - 1/(sqrt6)hatj - 1/(sqrt6)hatk" ")|)#