How do you normalize  <3,1,5>?

Dec 15, 2015

$< \frac{3}{\sqrt{35}} , \frac{1}{\sqrt{35}} , \frac{5}{\sqrt{35}} >$

Explanation:

First, you have to calculate for the magnitude of the vector .

$| | v | | = \sqrt{{3}^{2} + {1}^{2} + {5}^{2}} = \sqrt{35}$

Second, divide the magnitude by each of the component of the vector.

$\frac{1}{\sqrt{35}} < 3 , 1 , 5 > = < \frac{3}{\sqrt{35}} , \frac{1}{\sqrt{35}} , \frac{5}{\sqrt{35}} >$