How do you normalize #(- 3 i + 12j -k)#?

1 Answer
Mar 14, 2018

Answer:

#1/sqrt(154)(-3\hati + 12\hatj - \hatk)#

Explanation:

You have to calculate the square root of the sum of squares (magnitude) of the vector:

#sqrt((-3)^2+(12)^2+(-1)^2) = sqrt(9+144+1) = sqrt(154)#

Now you simply divide the entire vector by this quantity to normalize:

#1/sqrt(154)(-3\hati + 12\hatj - \hatk)#