How do you normalize (−3i+j−k)?

1 Answer
David G.
Mar 24, 2016

To normalise a vector we divide each of its elements by the length of the vector. First find the length: r=√(−3)2+12+(−1)2=√11≈3.3. The normalised vector can be written as (−3√11i+1√11j−1√11k) or (−33.3i+13.3j−13.3k).

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