How do you normalize (−4i−5j+2k)?

1 Answer
F. Javier B.
Apr 9, 2018

Dividing by his module

Explanation:

First: Lets calculate module √(−4)2+(−5)2+22=√45=3√5

Now, lets considered the vector (−43√5,−53√5,23√5). This vector has module =1

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