How do you normalize #(i+2j+2k)#?

1 Answer
Jul 26, 2018

Answer:

The answer is #=<1/3,2/3,2/3>#

Explanation:

To normalize a vector #veca#, calculate

#hata=veca/(||veca||)#

Here,

#veca = <1,2,2>#

The norm is

#||veca ||= ||<1,2,2>|| = sqrt(1^2+2^2+2^2)#

#=sqrt(1+4+4)#

#=sqrt9#

#=3#

Therefore,

#hata=1/3 <1,2,2> = <1/3,2/3,2/3>#