How do you order from least to greatest #{5.4, 537/100, 5.09, sqrt29}#?

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Answer 1 · 2016-10-24T07:47:45

#5.09 < 537/100 < sqrt29 < 5.4#

Convert them all to decimal form. Then they are easy to compare.

You can use fraction form because #sqrt 29# is irrational and cannot be written as a fraction.

Compare the digits in the first decimal place...

#""5.4 = 5.40" "larr# biggest

#537/100 = 5.37" "larr# second smallest

#5.09 = 5.09" "larr# smallest

#sqrt29 = 5.385" "larr# second biggest

Answer using the original numbers:

#5.09 < 537/100 < sqrt29 < 5.4#