# How do you perform the operation and write the result in standard form given (3+2i)-(6+13i)?

Apr 3, 2017

Given the difference between complex numbers two,

$\left(a + b i\right) - \left(c + \mathrm{di}\right)$,

the difference is:

$\left(a - c\right) + \left(b - d\right) i$

#### Explanation:

Given: $\left(3 + 2 i\right) - \left(6 + 13 i\right)$

$\left(3 + 2 i\right) - \left(6 + 13 i\right) = 3 - 6 + \left(2 - 13\right) i$

$\left(3 + 2 i\right) - \left(6 + 13 i\right) = - 3 - 11 i$