How do you plot a point (4, -3) on the line with slope m=0?

May 1, 2018

See the graph. You would have to mark the point $\left(4 , - 3\right)$ on the line $y = - 3$

Explanation:

You have a point on the line and its slope. By the Point-Slope form, you may compute the equation of this line.

$\left(y - {y}_{1}\right) = m \left(x - {x}_{1}\right)$
$\implies \left(y - \left(- 3\right)\right) = 0 \left(x - 4\right)$
$\implies y + 3 = 0$
$\implies y = - 3$

Thus you must plot the line $y = - 3$ and mark(4, -3) on it. Only lines parallel to the x-axis have slope 0. Thus it is a line parallel to the x axis at a distance 3 from it in the negative direction.
graph{y = -3 + 0x [-7.9, 7.9, -3.95, 3.95]}