How do you plot a point (4, -3) on the line with slope m=0?

1 Answer
May 1, 2018

Answer:

See the graph. You would have to mark the point #(4, -3)# on the line #y = -3#

Explanation:

You have a point on the line and its slope. By the Point-Slope form, you may compute the equation of this line.

#(y - y_1) = m(x - x_1)#
#implies (y - (-3)) = 0(x - 4)#
#implies y + 3 = 0#
#implies y = -3#

Thus you must plot the line #y= - 3# and mark(4, -3) on it. Only lines parallel to the x-axis have slope 0. Thus it is a line parallel to the x axis at a distance 3 from it in the negative direction.
graph{y = -3 + 0x [-7.9, 7.9, -3.95, 3.95]}