How do you prove #1/(1+sin) + 1/(1-sin) = 2sec^2# ?

1 Answer
Jim G.
Feb 5, 2016

see explanation

Explanation:

To prove trig identity either manipulate the left side into the form of the right side or the right side into the form of the left side or manipulate both sides together until they agree.

choose left side:

LHS = # 1/(1+sinx) + 1/(1-sinx) = (1-sinx+1+sinx)/((1+sinx)(1-sinx))#

( distribute brackets on denominator)

# = 2/(1 - sin^2x)#

now #(1 - sin^2x) = cos^2x#

# rArr 2/(1 - sin^2x) = 2/(cos^2x) = 2sec^2x color(black)(" = RHS ")#

Related questions
See all questions in Proving Identities
Impact of this question
15614 views around the world
You can reuse this answer
Creative Commons License