How do you prove #(1-2cos^2theta)/(sinthetacostheta)=tantheta-cottheta#?

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Answer 1 · 2016-10-07T15:57:30

see below

#(1-2cos^2theta)/(sintheta cos theta) = tan theta-cot theta#

Right Side:#=tan theta-cot theta#

#=sin theta/cos theta - cos theta/sin theta#

#=(sin^2 theta-cos^2 theta)/(sin theta cos theta)#

#=(1-cos^2 theta -cos^2 theta)/(sin theta cos theta)#

#=(1-2cos^2 theta)/(sin theta cos theta)#

#:.=#Left Side