How do you prove # 1/(secx-tanx) - 1/(secx+tanx)=2tanx#?

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Answer 1 · 2016-05-11T18:13:50

see below

Use Property: #sec^2x=1+tan^2x#

Left Side:#=1/(secx-tanx) -1/(secx+tanx)#

#=(secx+tanx-(secx-tanx))/((secx-tanx)(secx+tanx))#

#=(secx+tanx-secx+tanx)/(sec^2x-tan^2x)#

#=(2tanx)/1#

#=2tanx#

#=# Right Side