How do you prove $sec^2(x)-tan^2(x)=1$ ?

Question

61372 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-20T16:06:39

See Below

Left Hand Side:: $sec^2(x)-tan^2x$

$=1/cos^2x -(sin^2x)/cos^2x$

$=(1-sin^2x)/cos^2x$

$=cos^2x/cos^2x$ -> Use Property $sin^2x+cos^2x=1$ and isolate $cos^2x$

$=cancel(cos^2x/cos^2x$

$=1$

$=$ Right Hand Side

How do you prove sec^2(x)-tan^2(x)=1sec^2(x)-tan^2(x)=1?