How do you prove #sec^2(x)-tan^2(x)=1#?

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Answer 1 · 2018-03-20T16:06:39

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Left Hand Side:: #sec^2(x)-tan^2x#

#=1/cos^2x -(sin^2x)/cos^2x#

#=(1-sin^2x)/cos^2x#

#=cos^2x/cos^2x#-> Use Property #sin^2x+cos^2x=1# and isolate #cos^2x#

#=cancel(cos^2x/cos^2x#

#=1#

#=# Right Hand Side