How do you prove #[(sec^6)x] (secxtanx) - [(sec^4)x] (secxtanx) = [(sec^5)x] [(tan^3)x] #?

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Answer 1 · 2016-04-01T12:38:45

#=Secxtanx(sec^6x-sec^4x)#
#=Secxtanxsec^4x(sec^2x-1)#
#=Secxtanxsec^4xtan^2x#
#=Sec^5xtan^3x#