How do you prove #sin(pi+x) = - sinx#? Double Angle Question: 1.) Express sin x/2 in terms of cos x Thank you so much!?

1 Answer
May 2, 2015

I) #sin (x + Pi) = - sin x#. There are 2 ways to prove:
a. By the trig unit circle,.
Example: x = Pi/3 (Quadrant I). And #(x + pi)# is in Quadrant III.
Then #sin (x + pi) = - sin x#.
b. By trig identity sin (a + b) = sin a.cos b + sin a. sin b
#sin (x + pi) = sin x cos pi + sin pi.cos x #Because cos pi = -1 and sin pi = 0.# then #sin (x + Pi) = -sin x#

2) #cos x = 1 - 2sin^2 (x/2)#
#sin^2 (x/2) = (1 - cos x)/2#

#sin (x/2) = + (or -) sqr[[(1 - cos x)]/2]#