How do you prove that #cot^2x * sec^2x = csc^2x#?

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Answer 1 · 2015-12-18T02:10:17

By definition, we have

Thus

#cot^2(x)sec^2(x) = (cos(x)/sin(x))^2(1/cos(x))^2#

#= cos^2(x)/sin^2(x)*1/cos^2(x)#

#=1/sin^2(x)#

#=(1/sin(x))^2#

#=csc^2(x)#