# How do you prove that the function: #T(x) = 1 / (abs(x-2)-x^2)# is continuous between [1.5,8]?

##### 1 Answer

Dec 10, 2016

#### Answer:

Only ( infinite ) discontinuities at

#### Explanation:

Besides the graph, I have provided some data for clarity. Further, the

given function is representing the couple

graph{y(x^2-|x-2|)+1=0 [-10, 10, -5, 5]}