# How do you prove the identity (tanx)/(cscx + cotx) = secx - 1?

$\tan \left(x\right) = \sin \frac{x}{c} 0 s \left(x\right)$
$\csc \left(x\right) = \frac{1}{\sin} \left(x\right)$
$\cot \left(x\right) = \cos \frac{x}{\sin} \left(x\right)$
$\sec \left(x\right) = \frac{1}{\cos} \left(x\right)$
${\sin}^{2} \left(x\right) + {\cos}^{2} \left(x\right) = 1$