# How do you rationalise the denominator of #8/(3-sqrt5)#?

##### 1 Answer

Apr 3, 2016

Multiply both numerator and denominator by

#### Explanation:

#8/(3-sqrt(5))#

#=(8*(3+sqrt(5)))/((3-sqrt(5))(3+sqrt(5)))#

#=(24+8sqrt(5))/(3^2-(sqrt(5))^2)#

#=(24+8sqrt(5))/(9-5)#

#=(24+8sqrt(5))/4#

#=6+2sqrt(5)#

The expression *conjugate* of