How do you reduce #24/216#?

1 Answer
Aug 4, 2016

#24/216=1/9#

Explanation:

To reduce any faction such as #24/216# one needs to

(i) either factorize each of the numerator and denominator and then cancel out common factors (similar to dividing). Using this

#24/216=(2xx2xx2xx3)/(2xx2xx2xx3xx3xx3)#

= #(1cancel2xxcancel2xxcancel2xxcancel3)/(cancel2xxcancel2xxcancel2xxcancel3xx3xx3)#

= #1/9#

(ii) Alternatively one can find GCD of numerator and denominator and then divide both by it. Here as #24# easily divides #216# (#9# times), #24# is GCD and result will be again #1/9#.