How do you reduce #\frac{60}{840}#?

1 Answer
Aug 5, 2017

#=1/14#

Explanation:

If you are trying to simplify a fraction and you do not know the HCF, you can simplify one step at a time.

#60/840" "larr (div10)/(div10)#

#= 6/84" "larr (div 2)/(div 2)#

#= 3/42" "larr (div3)/(div3)#

#=1/14#

The order is which you simplify does not matter at all.
I could also have simplified by #12# at the start.

#60/840" "larr(div12)/(div12)#

#=5/70" "larr (div5)/(div5)#

#= 1/14#