How do you reduce to lowest term (x^3-3x)/(x^2-3x)?

Nov 15, 2016

((x^2 -3))/((x-3)

$x \ne 0 \mathmr{and} x \ne 3$

Explanation:

Find factors of the numerator and denominator

$\frac{{x}^{3} - 3 x}{{x}^{2} - 3 x}$

=$\frac{x \left({x}^{2} - 3\right)}{x \left(x - 3\right)} \text{ } \leftarrow x \ne 0 \mathmr{and} x \ne 3$

=((x^2 -3))/((x-3)