# How do you rewrite 1/(3y^4) using negative exponents?

${y}^{-} \frac{4}{3}$
Using ${a}^{m} = \frac{1}{a} ^ - m \Leftrightarrow {a}^{-} m = \frac{1}{a} ^ m$
$\Rightarrow \frac{1}{3 {y}^{4}} = \frac{1}{3} \times {y}^{-} 4 = {y}^{-} \frac{4}{3}$