How do you rewrite #(2/3)^3 = 8/27# in logarithm form?                 

1 Answer
Feb 18, 2015

So a logarithm is basically a function that allows you to answer the question, to what power must I raise this number to get that number?

Just like in the following diagram:

So you have the number (2/3), you have the power (3), and you have the desired result (8/27). Now, all you need to do is rearrange it according to the diagram.

You should end up with:

#log_(2/3)(8/27) = 3#

Hope that helped :)