How do you rewrite #f(x) = 2(x-1)^2+3# from vertex form to standard form?

1 Answer
Sep 6, 2017

#f(x)=2x^2-4x+5#

Explanation:

The equation is already in vertex form i.e. #f(x)=a(x-h)^2+k#, with #(h,k)# as vertex. Here we have vertex as #(1,3)#.

Standard form of equation is #f(x)-av^2+bx+c# and for this we just need to expand RHS, which can be done as follows:

#f(x)=2(x-1)^2+3#

= #2(x^2-2x+1)+3#

= #2x^2-4x+2+3#

= #2x^2-4x+5#