# How do you rewrite the equation of the circle (x + 2)^2 + (y + 5)^2 = 9 in general form?

Jan 5, 2016

${\left(x - \left(- 2\right)\right)}^{2} + {\left(y - \left(- 5\right)\right)}^{2} = {3}^{2}$

#### Explanation:

This basically is in the general form of a circle:

${\left(x - h\right)}^{2} + {\left(y + k\right)}^{2} = {r}^{2}$

You could, however, make the values of $h , k$ and $r$ more explicit in the circle equation you provided.

${\left(x + 2\right)}^{2} + {\left(y + 5\right)}^{2} = 9$

The equivalent form of this that better matches the general form of a circle is:

${\left(x - \left(- 2\right)\right)}^{2} + {\left(y - \left(- 5\right)\right)}^{2} = {3}^{2}$

Thus, the center is $\left(- 2 , - 5\right)$ and the radius is $3$.