# How do you rewrite with fractional exponents for 5sqrtx?

$5 \sqrt{x} = 5 {x}^{\frac{1}{2}}$
One of the laws of exponents is ${\left({x}^{a}\right)}^{b} = {x}^{a b}$
So ${\left({x}^{\frac{1}{2}}\right)}^{2} = {x}^{\frac{1}{2} \cdot 2} = {x}^{1} = x$
So ${x}^{\frac{1}{2}}$ certainly behaves like $\sqrt{x}$