How do you rewrite #y=10x+9/2# in standard form?

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Answer 1 · 2018-04-17T01:34:09

#10x-y=-9/2#

Given:

#y=10x+9/2# is a linear equation in slope-intercept form.

The standard form of a linear equation is #Ax+By=C#, where #A#, #B#, and #C# are integers, and #A# is positive if at all possible.

To convert #y=10x+9/2# to standard form, subtract #10x# from both sides.

#-10x+y=9/2#

Multiply both sides by #-1#. This will reverse the signs and make #A# positive.

#10x-y=-9/2#

graph{(y-10x-9/2)(-y+10x+9/2)=0 [-12.35, 12.96, -4.76, 7.9]}