SlopeIntercept Form
Key Questions

Answer:
#m# is the slope, while#b# is the yintercept.Explanation:
Any linear equation has the form of
#y=mx+b# 
#m# is the slope of the equation 
#b# is the yintercept
The slope of the line,
#m# , is found by#m=(y_2y_1)/(x_2x_1)# where
#(x_1,y_1)# and#(x_2,y_2)# are the coordinates of any two points in the line.The yintercept,
#b# , is found by plugging in#x=0# into the equation, which results in#y=b# , and therefore is the yintercept.In some cases, if the equation is already arranged for you nicely, like
#y=3x+5# , we can easily find the yintercept for this line, which is#5# .Other times, the equation might not be arranged nicely, with cases such as
#1/2x+3y=5# , in which we solve for the yintercept:#1/2x+3y=4# #3y=41/2x# #y=(1/2x+4)/3# #y=1/6x+4/3# So, the yintercept of this line is
#4/3# . 

The
#y# intercept#b# can be found by reading the#y# axis where the graph hits the yaxis, and the slope#m# can be found by finding any two distinct points#(x_1,y_1)# and#(x_2,y_2)# on the graph, and using the slope formula below.#m={y_2y_1}/{x_2x_1}# .
I hope that this was helpful.

Answer:
#y = mx + b# Where:
#m# is the slope of the line.
#b# is the yintercept of the line.Explanation:
Consider
#y = x# graph{y=x [10, 10, 5, 5]}
In this equation, the coefficient to
#x# is 1 and our yintercept is 0.We could think of that equation as looking like:
#y = 1x + 0# Notice that the graphed line has a "riseoverrun" of
#1/1# which is just 1 and the line passing through the yaxis at#y=0#