How do you rewrite $y = - 4 cos (2 x + (\frac{π}{2})) + 1$ $y=-4cos(2x+(pi/2))+1$ as a sine function?

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Answer 1 · 2015-05-15T05:51:44

since on the trig unit circle: $cos (2 x + \frac{π}{2}) = sin (2 x),$ $cos (2x + pi/2) = sin (2x),$ then

$y = - 4 sin (2 x) + 1$ $y = -4sin (2x) + 1$

How do you rewrite y=−4cos(2x+(π2))+1y=-4cos(2x+(pi/2))+1 as a sine function?