How do you set up and solve the following system using augmented matrices #3x-2y=8, 6x-4y=1#?

1 Answer
Mar 8, 2017

Answer:

No solution

Explanation:

The typesetting here does not support row augmented matrices.

But, if we are going with: #3x-2y=8, 6x-4y=1# ...then we start with:

#((3, -2),(6, -4))((8),(1))#

However, there is an immediate problem, we have linearly dependent rows, this is a singular matrix :(

#((3, -2),(6, -4)) = ((1/2(6), 1/2(-4)),(6, -4))#

So this either has no solutions or infinitely many:

#((3, -2),(6, -4)) ((x),(y)) = ((8),(1))#

Then go back and look at the equations and you will see that they represent parallel lines:

#3x-2y=color(red)(8)#

# 2(3x)-2(2y)=color(blue)(2(1/2))#